(5a+9)=(9a^2-2a-5)

Solution for (5a+9)=(9a^2-2a-5) equation:

(5a+9)=(9a^2-2a-5)

We move all terms to the left:

(5a+9)-((9a^2-2a-5))=0

We get rid of parentheses

5a-((9a^2-2a-5))+9=0


We calculate terms in parentheses: -((9a^2-2a-5)), so:

(9a^2-2a-5)

We get rid of parentheses

9a^2-2a-5

Back to the equation:

-(9a^2-2a-5)


We get rid of parentheses

-9a^2+5a+2a+5+9=0

We add all the numbers together, and all the variables

-9a^2+7a+14=0

a = -9; b = 7; c = +14;
Δ = b2-4ac
Δ = 72-4·(-9)·14
Δ = 553
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{553}}{2*-9}=\frac{-7-\sqrt{553}}{-18}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{553}}{2*-9}=\frac{-7+\sqrt{553}}{-18}
$